In this blog post, we will answer a question that many chemistry students have been struggling with. The question is what volume of N2 will react completely with 29.2 L H2 to produce NH3? To find the answer, you must first use Graham’s law of effusion to determine the rate at which molecules escape from an enclosure and then plug in some numbers. The following equation can be used: Rate = (n1*V1)/(n2*V2) Where n1 is the number density of N 2 molecules in the container on left; V1 is its total volume; n2 is the number density of H 2 molecules in container on right; V2 is its total volume, and rate is the number of N atoms produced per second. The equation will be solved for V, which in this case would be the total volume on right side: V = (n*V)/(n-r) Where n is the number density of H molecules outside container; V is its total volume; r is a constant equal to 0 if both containers contain gas at same temperature and pressure or equal to -l/kT otherwise where l equals Avogadro’s Number and k equals Boltzmann’s Constant. For simplicity sake, we’ll say that they are both 600 mmhg at 100 degrees Celsius so r=0. The equation then becomes V=14 L as that it